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Hydraulic Jump, Froude Number, and Critical Depth in Rectangular Channels
Fr > 1 can jump to a sequent depth. Bélanger relation, energy dissipation in stilling basins, and how critical depth sits between the two.
Updated 16 August 2026Solver360 Hydraulics10 min read
Key takeaways
- Fr = V/√(gy). Fr < 1 subcritical, Fr = 1 critical, Fr > 1 supercritical.
- Bélanger: y2/y1 = ½(−1 + √(1+8 Fr1²)).
- Energy loss ΔE = (y2−y1)³ / (4 y1 y2) is why stilling basins work.
- Undular jumps (Fr 1–1.7) dissipate little energy.
A hydraulic jump is a rapid conversion from supercritical to subcritical flow. Depth rises, velocity falls, and a roller dissipates energy. It is classified by the upstream Froude number.
Froude and critical depth
Fr = V / √(g y)
yc = (Q² / (g b²))^{1/3} (rectangular)
| Fr1 | Jump type | Notes |
|---|---|---|
| 1.0–1.7 | Undular | Little dissipation, wavy surface |
| 1.7–2.5 | Weak | Oscillating; poor stilling |
| 2.5–4.5 | Oscillating | Common design range |
| 4.5–9 | Steady / strong | Good energy kill |
| > 9 | Strong | Spray, air, rough basin |
Sequent depth and energy
y2/y1 = ½ (−1 + √(1 + 8 Fr1²))
ΔE = (y2 − y1)³ / (4 y1 y2)
Example: b = 2 m, y1 = 0.35 m, Q = 1.8 m³/s. V1 = 2.57 m/s, Fr1 = 1.39 (undular). yc = 0.43 m. y2 ≈ 0.54 m and ΔE is small. Raise Q or drop y1 until Fr1 > 4.5 if you need a stilling basin that actually dissipates energy.
Open solver: Uniform flow into the jumpOpen solver: Weir (often upstream of a jump)Frequently asked questions
Not as written. The sequent-depth relation changes with the section shape. Use a momentum balance on the actual area, or a tabulated jump chart.
Keywords
hydraulic jump calculatorfroude number open channelcritical depth rectangular channelbelanger sequent depthstilling basin energy dissipationsupercritical flow
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